Spectral Theorem
If \( \mA = \mA^T \), a symmetric matrix, then \( \mQ^T = \mQ^{-1} \). So,
$$ \mA = \mQ \mLambda \mQ^T $$
In other words, the eigendecomposition of a symmetric matrix leads to an orthogonal matrix.
In the next demo, a replica of the previous transformation recovery demo, but with symmetry constraints on \( \mA \), check out the first step.
\( \mQ^T \vx \).
Since \( \mQ \) is orthogonal, and so is its inverse, there is no stretching/shrinking in the first step.
Only rotation. Any stretching or shrinking is happening in the second step \( \mLambda \mQ^T \vx \).
Check also that the eigenvectors (eig row 1 and eig row 2) are always orthonormal.